![]() ![]() 20 Iron Rod (20 Iron Ingot) + 100 Screw/min (25 Iron Ingot) into 4 Rotor/min: 4 : 45 compression.10 Iron Rod/min into 40 Screw/min: 4 : 1 inflation.15 Iron Ingot/min into 15 Iron Rod/min: 1 : 1 compression.A smaller number of belts can optimize any space between or within modules without 'only fitting in 9 out of the 10 belts needed'Īs resources go through stages of production, they can be compressed into a smaller number of items. If a module requires a large number of belts, adding modules means finding space for these belts or start the production line elsewhere. Building additional modules that require a large number of belts means acquiring a proportional number of resources before being effective.Īdditionally, this helps finding space to get belts to the starting point of a production line. ![]() Limiting inputs as much as possible helps when expanding. This production line requires 2 inputs of Iron Ingots (1 for Iron Wire, 1 for Steel Ingots) and Coal (dedicated to Steel Ingot), all accomplishable within three 780 items/min/belt.
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